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71 changes: 71 additions & 0 deletions Arrays-algos/mountainSubarrayProblem.cpp
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// https://practice.geeksforgeeks.org/problems/mountain-subarray-problem/1

#include <bits/stdc++.h>
using namespace std;

class Solution{
public:
vector<bool> processQueries(int a[], int n, vector<pair<int, int>> &queries,
int q) {

vector<bool>ans;
int left[n], right[n];
left[0]=0;
right[n-1]=n-1;
int k=0;

// left[i] stores the last index on left side which is increasing
// i.e. greater than its previous element
for(int i=1; i<n; i++)
{
if(a[i-1]<a[i])
k=i;
left[i]=k;
}
// right[i] will store the first index on the right side which is decreasing
// i.e. greater than its next element.
for(int i=n-2; i>=0; i--)
{
if(a[i+1]<a[i])
k=i;
right[i]=k;

}

for(auto x: queries)
{
int l= x.first;
int r= x.second;

if(left[r]<=right[l])
ans.push_back(true);
else
ans.push_back(false);
}
return ans;
}
};

int main() {
int tc;
cin >> tc;
while (tc--) {
int n, i, q;
cin >> n;
int a[n];
for (i = 0; i < n; i++) {
cin >> a[i];
}
cin >> q;
vector<pair<int, int>> queries(q);
for (i = 0; i < q; i++) {
cin >> queries[i].first >> queries[i].second;
}
Solution obj;
auto v = obj.processQueries(a, n, queries, q);
for (bool u : v) {
cout << (u ? "Yes\n" : "No\n");
}
}
return 0;
}