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Support sync thenables for lazy() #14626
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              | Original file line number | Diff line number | Diff line change | 
|---|---|---|
|  | @@ -47,6 +47,7 @@ export function readLazyComponentType<T>(lazyComponent: LazyComponent<T>): T { | |
| lazyComponent._status = Pending; | ||
| const ctor = lazyComponent._ctor; | ||
| const thenable = ctor(); | ||
| lazyComponent._result = thenable; | ||
| thenable.then( | ||
| moduleObject => { | ||
| if (lazyComponent._status === Pending) { | ||
|  | @@ -73,7 +74,10 @@ export function readLazyComponentType<T>(lazyComponent: LazyComponent<T>): T { | |
| } | ||
| }, | ||
| ); | ||
| lazyComponent._result = thenable; | ||
| // Check if it resolved synchronously | ||
| if (lazyComponent._status === Resolved) { | ||
| return lazyComponent._result; | ||
| } | ||
| There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. We could also do the same for failure. But doesn't seem worth the extra code to me. Could be a recursive call but then there's more risk of messing it up and going into a stack overflow. Meh. | ||
| throw thenable; | ||
| } | ||
| } | ||
|  | ||
  
    
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This is still needed because we read thenable from
lazyComponent._resultwhile it's pending. If we keep the assignment, it will overwrite sync thenables. But if we remove it at all, we will thrownullinstead of thenable. This fixes both cases.There was a problem hiding this comment.
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You still need the assignment, but I don't think you need to move it up here. If you keep it right after the early return branch you added on line 78-80, then there's always a single assignment.