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Description
By default, ImageBuilder uses an explicit build context of the Dockerfile's location:
docker-tools/src/Microsoft.DotNet.ImageBuilder/src/ViewModel/PlatformInfo.cs
Lines 59 to 62 in 14b1496
| string dockerfileWithBaseDir = Path.Combine(baseDirectory, model.ResolveDockerfilePath(baseDirectory)); | |
| DockerfilePath = PathHelper.NormalizePath(dockerfileWithBaseDir); | |
| BuildContextPath = PathHelper.NormalizePath(Path.GetDirectoryName(dockerfileWithBaseDir)); | |
| DockerfilePathRelativeToManifest = PathHelper.TrimPath(baseDirectory, DockerfilePath); |
In some cases it's desirable to access content from outside the Dockerfile's directory. For example, when building .NET projects, you may need to access a Directory.Build.Props or NuGet.config located in a parent directory.
There are two ideas I came up with for implementing this:
Option 1: explicit path
This option would allow you to set the explicit path to the build context. The path would be relative to the manifest.
Option 2: limited choices
The other option would allow you to choose between having the build context be the Dockerfile's parent directory (the default, today) or the manifest's parent directory. This could be via an enum:
{
"dockerfile": "src/ImageBuilder/Dockerfile.linux",
"buildContext": "Manifest", // OR "Dockerfile"
"os": "linux",
"osVersion": "azurelinux",
"tags": {
"linux-amd64": {},
"linux-amd64-$(UniqueId)": {}
}
},Or a boolean:
{
"dockerfile": "src/ImageBuilder/Dockerfile.linux",
"manifestRelativeBuildContext": "true", // "false" is the default
"os": "linux",
"osVersion": "azurelinux",
"tags": {
"linux-amd64": {},
"linux-amd64-$(UniqueId)": {}
}
},Metadata
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{ "dockerfile": "src/ImageBuilder/Dockerfile.linux", "buildContext": "path/to/my/preferred/context", "os": "linux", "osVersion": "azurelinux", "tags": { "linux-amd64": {}, "linux-amd64-$(UniqueId)": {} } },