Codespell don't handle KeyboardInterrupt exception

[jcubic]

This should be catched and the program should stop gracefully but instead show default stack trace:

^CTraceback (most recent call last):
  File "/home/kuba/.local/bin/codespell", line 8, in <module>
    sys.exit(_script_main())
             ^^^^^^^^^^^^^^
  File "/home/kuba/.local/lib/python3.12/site-packages/codespell_lib/_codespell.py", line 1017, in _script_main
    return main(*sys.argv[1:])
           ^^^^^^^^^^^^^^^^^^^
  File "/home/kuba/.local/lib/python3.12/site-packages/codespell_lib/_codespell.py", line 1185, in main
    bad_count += parse_file(
                 ^^^^^^^^^^^
  File "/home/kuba/.local/lib/python3.12/site-packages/codespell_lib/_codespell.py", line 903, in parse_file
    check_matches = extract_words_iter(line, word_regex, ignore_word_regex)
                    ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
  File "/home/kuba/.local/lib/python3.12/site-packages/codespell_lib/_codespell.py", line 793, in extract_words_iter
    return list(word_regex.finditer(_ignore_word_sub(text, ignore_word_regex)))
           ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
KeyboardInterrupt

There is no need to show KeyboardInterrupt exception stack trace.