[Arith] Added simplification rule for multiple equality compares #15628
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The expression `(x==y) && (x==z)` requires that `y==z`. When `y` and `z` are constants, this can allow better constant folding by rewriting `(x==c1) && (x==c2)` into `(x==c1) && (c1==c2)`. This commit adds the above rewrite, and the corresponding rewrite of the negative expression.
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The expression
(x==y) && (x==z)requires thaty==z. Whenyandzare constants, this can allow better constant folding by rewriting(x==c1) && (x==c2)into(x==c1) && (c1==c2).This commit adds the above rewrite, and the corresponding rewrite of the negative expression. This was initially part of #15627, but does not depend on Relax features, and is split out in order to upstream into TVM main.