Revert "test: adjust number of iterations of flakey test"

This reverts commit ce71d5c.

Author: baileympearson

test/integration/server-selection/server_selection.prose.operation_count.test.ts

@@ -19,7 +19,7 @@ const failPoint = {
 
 const POOL_SIZE = 100;
 
-async function runTaskGroup(collection: Collection, count: 10 | 100 | 500) {
+async function runTaskGroup(collection: Collection, count: 10 | 100) {
   for (let i = 0; i < count; ++i) {
     await collection.findOne({});
   }
@@ -147,19 +147,13 @@ describe('operationCount-based Selection Within Latency Window - Prose Test', fu
   it('equally distributes operations with both hosts are fine', TEST_METADATA, async function () {
     const collection = client.db('test-db').collection('collection0');
 
-    const numberTaskGroups = 10;
-    const numberOfTasks = 500;
-    const totalNumberOfTasks = numberTaskGroups * numberOfTasks;
-
     // Step 8: Start 10 concurrent threads / tasks that each run 100 findOne operations with empty filters using that client.
-    await Promise.all(
-      Array.from({ length: numberTaskGroups }, () => runTaskGroup(collection, numberOfTasks))
-    );
+    await Promise.all(Array.from({ length: 10 }, () => runTaskGroup(collection, 100)));
 
     // Step 9: Using command monitoring events, assert that each mongos was selected roughly 50% of the time (within +/- 10%).
     const [host1, host2] = seeds.map(seed => seed.split(':')[1]);
-    const percentageToHost1 = (counts[host1] / totalNumberOfTasks) * 100;
-    const percentageToHost2 = (counts[host2] / totalNumberOfTasks) * 100;
+    const percentageToHost1 = (counts[host1] / 1000) * 100;
+    const percentageToHost2 = (counts[host2] / 1000) * 100;
     expect(percentageToHost1).to.be.greaterThan(40).and.lessThan(60);
     expect(percentageToHost2).to.be.greaterThan(40).and.lessThan(60);
   });