parse literals more like Postgres #1807
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sql/parser/encode.go
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Why don't you append the strMod byte above where the opening ' is appended?
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done. Remnants from earlier code where I hoped not to have to iterate twice.
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with this change * rewrote SQL escaping. It'll output an escaped string when it has to, or when a single-quote or backslash appears (the former could be written as '', but this is more awkward to implement; the latter needs escaping only in an escaped string, which would require an extra pass through the string prior to beginning the encoding - not worth it). * no escaping of "; Postgres doesn't do it * dissect and update all the test cases affected by this and add some new ones. found via go-fuzz, ping @dvyukov.
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a single-quote or backslash appears (the former could be written as '', but
this is more awkward to implement; the latter needs escaping only in an
escaped string, which would require an extra pass through the string prior
to beginning the encoding - not worth it).
found via go-fuzz, ping @dvyukov.