Bugfix: TypeParameter equality does not check for unconstrained types, see #119

Author: sebastian-lenz

bin/typedoc.js

@@ -6851,9 +6851,21 @@ var td;
              * @returns TRUE if the given type equals this type, FALSE otherwise.
              */
             TypeParameterType.prototype.equals = function (type) {
-                return type instanceof TypeParameterType &&
+                if (!(type instanceof TypeParameterType)) {
+                    return false;
+                }
+                var constraintEquals;
+                if (this.constraint && type.constraint) {
+                    constraintEquals = type.constraint.equals(this.constraint);
+                }
+                else if (!this.constraint && !type.constraint) {
+                    constraintEquals = true;
+                }
+                else {
+                    return false;
+                }
+                return constraintEquals &&
                     type.isArray == this.isArray &&
-                    type.constraint.equals(this.constraint) &&
                     type.name == this.name;
             };
             /**

src/td/models/types/TypeParameterType.ts

@@ -39,9 +39,21 @@ module td.models
          * @returns TRUE if the given type equals this type, FALSE otherwise.
          */
         equals(type:TypeParameterType):boolean {
-            return type instanceof TypeParameterType &&
+            if (!(type instanceof TypeParameterType)) {
+                return false;
+            }
+
+            var constraintEquals;
+            if (this.constraint && type.constraint) {
+                constraintEquals = type.constraint.equals(this.constraint);
+            } else if (!this.constraint && !type.constraint) {
+                constraintEquals = true;
+            } else {
+                return false;
+            }
+
+            return constraintEquals &&
                 type.isArray == this.isArray &&
-                type.constraint.equals(this.constraint) &&
                 type.name == this.name;
         }