Fix at-inferred with a single dot-broadcast op

Author: Keno

base/broadcast.jl

@@ -1079,9 +1079,10 @@ function __dot__(x::Expr)
         Expr(x.head, x.args[1], dotargs[2])
     else
         if x.head == :&& || x.head == :||
-            Base.depwarn("""
-                using $(x.head) expressions in @. is deprecated; in the future it will
-                become elementwise. Break the expression into smaller parts instead.""", nothing)
+            error("""
+                Using `&&` and `||` is disallowed in `@.` expressions.
+                Use `&` or `|` for elementwise logical operations.
+                """)
         end
         head = string(x.head)
         if last(head) == '=' && first(head) != '.'

stdlib/Test/src/Test.jl

@@ -1256,6 +1256,7 @@ function get_testset_depth()
 end
 
 _args_and_call(args...; kwargs...) = (args[1:end-1], kwargs, args[end](args[1:end-1]...; kwargs...))
+_materialize_broadcasted(f, args...) = Broadcast.materialize(Broadcast.broadcasted(f, args...))
 """
     @inferred f(x)
 
@@ -1294,7 +1295,12 @@ macro inferred(ex)
         ex = Expr(:call, :getindex, ex.args...)
     end
     Meta.isexpr(ex, :call)|| error("@inferred requires a call expression")
-
+    farg = ex.args[1]
+    if isa(farg, Symbol) && first(string(farg)) == '.'
+        farg = Symbol(string(farg)[2:end])
+        ex = Expr(:call, GlobalRef(Test, :_materialize_broadcasted),
+            farg, ex.args[2:end]...)
+    end
     Base.remove_linenums!(quote
         let
             $(if any(a->(Meta.isexpr(a, :kw) || Meta.isexpr(a, :parameters)), ex.args)