Update and rename RunningSum.cpp to easy-1480-running_sum_of_1d_array.cpp

Author: matthewgoembel

Codes/RunningSum.cpp

@@ -0,0 +1,52 @@
+// Given an array nums, we define a running sum of an array as runningSum[i] = sum(nums[0]…nums[i]).
+
+// Return the running sum of nums.
+
+ 
+
+// Example 1:
+
+// Input: nums = [1,2,3,4]
+// Output: [1,3,6,10]
+// Explanation: Running sum is obtained as follows: [1, 1+2, 1+2+3, 1+2+3+4].
+
+// Example 2:
+
+// Input: nums = [1,1,1,1,1]
+// Output: [1,2,3,4,5]
+// Explanation: Running sum is obtained as follows: [1, 1+1, 1+1+1, 1+1+1+1, 1+1+1+1+1].
+
+// Example 3:
+
+// Input: nums = [3,1,2,10,1]
+// Output: [3,4,6,16,17]
+
+
+class Solution {
+public:
+    vector<int> runningSum(vector<int>& nums) {
+        vector<int> sum;
+        sum.push_back(nums[0]);
+        int n=0;
+        for(int i=1;i<nums.size();i++){
+            sum.push_back(sum[i-1]+nums[i]);
+        }
+        return sum;
+    }
+};
+/*
+0ms solution
+
+class Solution {
+public:
+    vector<int> runningSum(vector<int>& nums) 
+    {
+        int n = nums.size();
+        for(int i = 1; i < n; i++)
+           nums[i] += nums[i-1];
+
+        return nums;   
+    }
+};
+
+*/